cbartlett714 cbartlett714
  • 01-03-2020
  • Chemistry
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How many grams are in 5.87x10^21 molecules of sulfur?

Respuesta :

Eduard22sly
Eduard22sly Eduard22sly
  • 01-03-2020

Answer:

0.312g

Explanation:

From Avogadro's hypothesis, 1mole of any substance contains 6.02x10^23 molecules. This means that 1mole of sulphur also contains 6.02x10^23 molecules

1mole of sulphur = 32g

If 1 mole(i.e 32g) of sulphur contains 6.02x10^23 molecules

Then, Xg of sulphur will contain 5.87x10^21 molecules i.e

Xg of sulphur = (32x5.87x10^21)/6.02x10^23 = 0.312g

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