ClaudioG641026 ClaudioG641026
  • 03-11-2022
  • Mathematics
contestada

Identify whether the problem is "Sum of Two Cubes" or "Difference of Cubes". Then, factor the problem.x^3 - 8

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AbbeyH764730 AbbeyH764730
  • 03-11-2022

We have in this case the difference of Perfect Cubes since we have:

[tex]x^3-8=x^3-2^3[/tex]

We know that this case can be factored as follows:

[tex]a^3-b^3=(a-b)\cdot(a^2+ab+b^2)[/tex]

If we have that:

a = x

b = 2

Then, we have:

[tex](x-2)\cdot(x^2_{}+2x+2^2)=(x-2)\cdot(x^2+2x+4)[/tex]

Therefore, the factored form of the perfect cube (for difference) is:

[tex]undefined[/tex]

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