ralph4497 ralph4497
  • 03-05-2018
  • Chemistry
contestada

Give the expression for the solubility product constant for baf2.

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Ishankahps
Ishankahps Ishankahps
  • 13-05-2018

Solubility product constant (Ksp) is applied to the saturated ionic solutions which are in equilibrium with its solid form. The solid is partially dissociated into its ions.

For the BaF, the dissociation as follows;
BaF
₂(s) ⇄ Ba²⁺(aq) + 2F⁻(aq)


Hence,
        Ksp = [Ba
²⁺(aq)] [F⁻(aq)]²

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